Try this

Arvind Kumar replied to Sathish N at 03-Jul-08 01:04

Private Sub PrintDocument1_PrintPage(ByVal sender As Object, ByVal e As_
System.Drawing.Printing.PrintPageEventArgs) Handles PrintDocument1.PrintPage
'PrintPage is the foundational printing event. This event gets fired for every
' page that will be printed
Static intCurrentChar As Int32
' declaring a static variable to hold the position of the last printed char
Dim font As New Font("Verdana", 14)
' initializing the font to be used for printing
Dim PrintAreaHeight, PrintAreaWidth, marginLeft, marginTop As Int32
With PrintDocument1.DefaultPageSettings
' initializing local variables that contain the bounds of the printing area rectangle
PrintAreaHeight = .PaperSize.Height - .Margins.Top - .Margins.Bottom
PrintAreaWidth = .PaperSize.Width - .Margins.Left - .Margins.Right
' initializing local variables to hold margin values that will serve
' as the X and Y coordinates for the upper left corner of the printing
' area rectangle.
marginLeft = .Margins.Left
marginTop = .Margins.Top
' X and Y coordinate
End With

If PrintDocument1.DefaultPageSettings.Landscape Then
Dim intTemp As Int32
intTemp = PrintAreaHeight
PrintAreaHeight = PrintAreaWidth
PrintAreaWidth = intTemp
' if the user selects landscape mode, swap the printing area height and width
End If

Dim intLineCount As Int32 = CInt(PrintAreaHeight / font.Height)
' calculating the total number of lines in the document based on the height of
' the printing area and the height of the font
Dim rectPrintingArea As New RectangleF(marginLeft, marginTop, PrintAreaWidth, PrintAreaHeight)
' initializing the rectangle structure that defines the printing area
Dim fmt As New StringFormat(StringFormatFlags.LineLimit)
'instantiating the StringFormat class, which encapsulates text layout information
Dim intLinesFilled, intCharsFitted As Int32
e.Graphics.MeasureString(Mid(RichTextBox1.Text, intCurrentChar + 1), font,_
New SizeF(PrintAreaWidth, PrintAreaHeight), fmt, intCharsFitted, intLinesFilled)
' calling MeasureString to determine the number of characters that will fit in
' the printing area rectangle
e.Graphics.DrawString(Mid(RichTextBox1.Text, intCurrentChar + 1), font,_
Brushes.Black, rectPrintingArea, fmt)
' print the text to the page
intCurrentChar += intCharsFitted
'advancing the current char to the last char printed on this page
< TextBox1.Text.Length Then
If intCurrentChar e.HasMorePages=True
'HasMorePages tells the printing module whether another PrintPage event should be fired
Else
e.HasMorePages = False
intCurrentChar = 0
End If
End Sub


Click here to sign in and reply. You could earn money via our $500 contest just for being helpful.
  Print sales Record - Sathish N  03-Jul-08 12:56 12:56:39 AM
      Try this - Arvind Kumar  03-Jul-08 01:04 1:04:46 AM
      You can do this.. - santhosh kumar  03-Jul-08 01:47 1:47:04 AM
View Posts